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Congratulations to Xiaotian (Eric) Ma for being the first to figure out this week's question. In making the decision over which college to attend, a simple decision rule might be to choose the college that, on average, provides the higher expected income. The probability of injury will govern the likelihood that the young athlete will ever play professionally or settle for a regular career with his bachelor's degree.
Thus, the expected value of attending each college can be calculated as:
EV(OSU) = (0.94)($1,700,000) + (0.06)($65,000) = $1,601,900
EV(UM) = (0.85)($1,250,000) + (0.15)($85,000) = $1,075,250
As Eric points out, OSU provides the young athlete with the better income potential.
2 comments:
For the OSU,
salary=1,700,000*0.94+65,000*0.06
=1,601,900
For the UW,
salary=1,250,000*0.85+85,000*0.15
=1,075,250
Based on the above, the student should attend the OSU, for 1,601,900 is more than 1,075,250
Hello, Dr. Delemeester.
This is Qi Wu. In point of view, this student will choose the UM, if all else constantly.
From the midpoint method, I guess that if the absolutely value of elastic is higher, changes will be easier.
In OSU
% change in price= 2*($17,000,000-$65,000)/($17,000,000+$65,000) =1.8527
In UM
% change in price= 2*($1,250,000-$85,000)/($1,250,000+$85,000) =1.8023
From these calculations, we can know the student is willing to go to the UM.
Furthermore, as it offered, the odds of a career-ending injury at UM are higher that OSU.
So ,I guess that the student will attend in the UM.
Thank you very much.
Qi Wu
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